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Language in C Interview Questions and Answers

Ques. What's wrong with the following declaration: char* ptr1, ptr2 ; get errors when I try to use ptr2 as a pointer.

Ans. char * applies only to ptr1 and not to ptr2. Hence ptr1 is getting declared as a char pointer, whereas, ptr2 is being declared merely as a char. This can be rectified in two ways :
char *ptr1, *ptr2 ;
typedef char* CHARPTR ; CHARPTR ptr1, ptr2 ;
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