Language in C вопросы и ответы для интервью
Question: Is the following code fragment correct?
Answer: No! Here, the variable x is first declared as an int so memory is reserved for it. Then it is qualified by a const qualifier. Hence, const qualified object is not a constant fully. It is an object with read only attribute, and in C, an object associated with memory cannot be used in array dimensions. |
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Самое полезное по оценкам пользователей:
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void main ()
{ int i = 0 , a[3] ;
a[i] = i++;
printf ("%d",a[i]) ;
} - Why doesn't the following code give the desired result?
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long int z = x * y ; - Why doesn't the following statement work?
char str[ ] = "Hello" ;
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